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| Figure 21, presence of resistor of 45 kO& ?' b! p/ a, q' S/ \0 m% l' s4 K
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; v2 f: t1 d6 F* u8 ~ | 60601-1(ed.2);am1;am2( m E0 e6 n2 N6 [
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; j. k1 ~; S3 E5 Q& SStandard(s)- (year and edition):: z( c, W' I$ g
IEC 60601-1:1988 Ed.27 X# _# j& t* L E; @9 x" z' ~3 h
Am1+Am28 m0 m( q) i/ u! q$ r$ N8 p4 l, K
Sub clause(s):+ h5 H1 g! k$ }
19) R6 }- R" I5 d' t- l
Sheet n°: 5348 l+ c Z9 v- c9 n) M0 ~
Subject:
7 c) {. B' r( rFigure 21, presence of resistor
' N1 {# R! H! ^* Q5 a& W# k3 p: Z0 aof 45 kO
7 Z( k# t1 O1 j v& VKey words: Decision taken at the 40th
/ ?2 G/ I$ k# [+ x: Kmeeting 2003
6 p& g# n$ V; _% x6 _5 o2 tQuestion:
+ x: {% u }0 X2 q' ]- b( | ^; x( u( \1 KShould the 45 kO resistor be used since the current is limited to 5 mA and the limit is 5 mA?2 V: L& Y+ o+ ^- R: G3 t0 C% H
Decision:% Z5 C- {- Y# m7 z s8 O% T' u
For the 1st edition, use the method of 2nd edition (use any resistance).( N! z* v5 k" t$ @
For 2nd edition, instead of using any resistance, you may also use alteration of the voltage or fuses., S1 ^' Q# t) K P* j
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发表于 2012-9-19 15:49
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