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. k# x' P$ k. e' a& r& u0 U
| Figure 21, presence of resistor of 45 kO' ^. y4 L$ S4 T; s+ ? Z2 s
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J! e7 [3 [& l- p- m | 60601-1(ed.2);am1;am24 ~: }6 A A& o% C/ K \
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7 M! t# Q7 \+ s: M* G- \$ vStandard(s)- (year and edition):
8 @- h, J7 q" nIEC 60601-1:1988 Ed.2
- O! S- O4 x9 N }! MAm1+Am2
) a0 J6 l0 u/ ]) e9 \1 PSub clause(s):! S( V) V* A5 `9 }0 }7 L: e9 `0 R7 o% F
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1 g6 D: N: Q7 s9 Q4 k2 OSheet n°: 534+ C) |* {7 R: m: r S
Subject:4 c- Z/ {, j2 O3 z E
Figure 21, presence of resistor" K- B, x0 d" b W3 q8 x% I& W
of 45 kO
8 L5 G0 S9 L. B' H" D5 w; r vKey words: Decision taken at the 40th
* ^- R8 g: `* q* Q3 D! cmeeting 20036 T. D5 f G& x3 r
Question:
9 v) a% J: z( XShould the 45 kO resistor be used since the current is limited to 5 mA and the limit is 5 mA?
3 e1 O, R" n8 j; X' C3 B. V6 {Decision:+ u7 ]" U6 ]* e. S: X. v
For the 1st edition, use the method of 2nd edition (use any resistance).+ W# `1 s% ?- t6 I$ M! |, X# N6 ?
For 2nd edition, instead of using any resistance, you may also use alteration of the voltage or fuses. m. K; L( ~1 |! T& t8 J. U
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发表于 2012-9-19 15:49
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