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| DSH 525
# O2 q' b9 ~/ \3 E4 ?+ h f9 d' i G0 Y4 F
| Applied force for internal parts
- Z, P1 D- w. A! G% v* K1 x | 13.2. C, }" o: N! E& K* k8 o+ k
| 60065(ed.6)
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* v6 F: g# g9 k1 k8 E; o+ @Standard:
# F9 P9 O$ {5 k4 e& T- n3 JIEC60065 6ed.1 ]5 A5 r0 Y& a3 |
Sub clause:5 w4 d9 ^+ E) @& l& ~! o
13.2$ H( Y. ?9 y" g' Q$ Q, D
Sheet No.
8 O, o5 {, o5 C# Y' e U: C+ K525
U' I1 x9 m1 f& C0 s/ jSubject1 y4 z* A2 D9 A( o% I8 `
Applied force for internal parts' ~! C7 Z( S( U4 O
Key words:
4 B/ U! x( b1 c) m. A+ N7 r6 x# Vforce for internal parts
! a2 l, J) R9 o* j4 ?Decision taken at the
2 i/ e3 J4 a* a4 a& U" h40th meeting 2003) C: C; B) E3 z% e
Question:( V: I% s0 e& i7 }: `% C3 n! a5 S
In clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied& ~9 F/ G2 I* N7 r: `
simultaneously while taking measurement of clearance. However, it is not specified that forces are
, F+ a7 S- s$ |applied to internal parts while taking measurements between two internal parts, ex. primary circuit; d5 [( ]2 x2 [6 \
component and secondary circuit component.1 V- t. |6 p8 v. Y) |$ v/ ]
Which is the appropriate method to measure clearance between two internal parts ?
" r0 r U2 }3 w* }7 U1 k P" Pa) 2N forces are applied to the both parts simultaneously.: I) Q) W/ r: e( z% r1 S7 `( i
b) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.( {7 [. I! ?, L- q* ~0 H1 L
c) Other opinion& {8 ]; \" z y. v* S' M2 ]
Decision:
8 q! V. b; h8 z- l- jFirst, a 2N force is applied to one part and removed. Then a 2N force is applied to the other
( P8 H2 X4 J' X9 b, L' _: ?. D+ Apart.
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4 U+ s* N) Q3 g; }9 l t, r" D' G3 \. S# I" i+ [6 S* i
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