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| DSH 525
- }* d) @& K. ~. E( ^
9 s9 d4 V$ q/ z' Y | Applied force for internal parts
0 T7 O: D4 S3 O$ T0 e | 13.21 g0 W- B3 t& t- A
| 60065(ed.6)+ s; C+ l) W& e$ w3 C
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3 [* ^1 Z7 J/ r9 lStandard: L4 r* K9 b7 p0 Z) D
IEC60065 6ed.' U: B& q! n- x) R
Sub clause:. p2 b: T) _( w |2 h7 Y% h
13.2* ? D- F5 f2 V0 P, ]
Sheet No.* C, M: q# W- z
525
9 T1 r a1 ^: G- E0 v U6 x8 nSubject7 k; u: B! K; m5 Y' w+ ~' u# c
Applied force for internal parts
; G& \) Y U0 H5 {Key words:- [2 P+ J, F. S1 F
force for internal parts
3 ~. Z, R* w9 d$ a) k5 G5 K# GDecision taken at the2 H0 O/ [! V) E8 W M0 X p
40th meeting 2003
/ t2 z1 V0 O9 x; k" KQuestion:
' k' E+ {' ^! ]( {, O, D, BIn clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied5 ^) f- e6 E5 O9 A {* \
simultaneously while taking measurement of clearance. However, it is not specified that forces are4 ^2 d. n# m+ K/ B3 V
applied to internal parts while taking measurements between two internal parts, ex. primary circuit
5 }9 p* w$ n# rcomponent and secondary circuit component.
. \. Y2 ^9 y& q) j' C8 }$ S# ^- LWhich is the appropriate method to measure clearance between two internal parts ?+ c2 _: S' y% t l) B# O5 X
a) 2N forces are applied to the both parts simultaneously.
: [ d& P- P2 T1 \$ c; F3 v& M; Fb) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one." D8 X3 u( c0 g% z' ?' B( ]
c) Other opinion- K1 W6 V# O) ^, `' [& c& C
Decision: ~+ Z8 A( |4 z& B8 c3 d) J
First, a 2N force is applied to one part and removed. Then a 2N force is applied to the other
* r/ s1 L7 t' z, d% W9 T8 Kpart.
" T8 e$ P4 X |/ O9 j8 e% u9 U: e1 \6 C) g3 y j+ x9 A
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