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| DSH 5257 J2 q+ p1 k; z: N( C7 U; v7 q
- G, e- \. R$ ]* C, ^0 A( [2 v
| Applied force for internal parts
3 z& n0 B: r2 _2 m8 e8 w8 K1 q | 13.29 ?6 D& k& M' N
| 60065(ed.6)
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Standard:8 Z' @7 M, k8 C. Q
IEC60065 6ed.7 V. A! F# v3 Q; o' P% A1 g: ~. d' K$ m1 F
Sub clause:9 z' {: F8 B0 l* ~) D2 _! u
13.2( m- v1 N- y0 H% f L
Sheet No.
0 a( }" Y' c6 y" `8 y( t0 ]5254 c1 Q' C' Q. A x$ A
Subject+ J. U( P( w O& R4 \
Applied force for internal parts0 v3 k5 i. p, L) h) X# O; G% K
Key words:
6 F+ ?0 u: x% x& Y, g6 w( I; u# Z. Mforce for internal parts w' E+ D7 n( _$ W9 f
Decision taken at the k+ N* n3 N! t( N# V9 ?* j
40th meeting 2003( b- f) }. r+ I+ m( `
Question:( v4 q' w; ~- c; S$ F
In clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied( K- z1 g2 A- H
simultaneously while taking measurement of clearance. However, it is not specified that forces are
/ r7 r( N3 K1 B6 }7 }applied to internal parts while taking measurements between two internal parts, ex. primary circuit
% J1 |! b2 E' s8 Zcomponent and secondary circuit component.
6 A3 y+ v/ n2 |Which is the appropriate method to measure clearance between two internal parts ?
( Q+ T# P6 c9 Z# C* i3 v" Xa) 2N forces are applied to the both parts simultaneously.
" N. {6 m5 h- K$ c5 \3 a# v9 Ib) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.3 Y) Y" h D, s3 J
c) Other opinion: q3 P {$ N: w$ k4 `( F
Decision:4 ?& H8 j& }9 B+ W, h
First, a 2N force is applied to one part and removed. Then a 2N force is applied to the other
4 N b$ l$ Y8 K, V8 lpart.
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