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发表于 2009-5-8 15:06
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引用第10楼franco于2009-05-07 20:39发表的 :
/ k0 d/ f- N* X8 {" m( E; Q8 nThe oscillating member is moved backwards and forwards through an angle of 90° (45° on
+ h5 N8 V% _; `either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
6 y. U6 }) U! S. tmin. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the + O! X0 H% I* O! H) n* D& r
sample is turned through 90° about the centre line of the cord guard.
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....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。
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翻译成中文的主要意思就是:% O* v% H0 _" h( S/ s6 t
$ e( h3 L4 u: e5 s% Y7 ] YThe oscillating member is moved backwards and forwards through an angle of 90° (45° on . U: t0 H1 J2 b% N
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
$ q& n' @( K5 n& d9 tmin. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。
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# x, G4 _. v) B$ o" |3 C: r0 V这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。
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, d* f2 o" A4 g2 L+ a8 r" c$ |After 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。) k/ L9 z) m2 i N6 H
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这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。
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! @( [! y) h M6 q u- R最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。; E; H3 o+ w3 i1 b
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这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。) l% h5 t2 I( U, v3 P
% M7 n! w; g; N9 o. T# t摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:* X' |# d; ~4 {$ V9 J
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A flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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