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发表于 2009-5-8 15:06
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引用第10楼franco于2009-05-07 20:39发表的 :
) e" n- K1 @# S1 KThe oscillating member is moved backwards and forwards through an angle of 90° (45° on
6 z: `3 Q$ H- u( zeither side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
: I5 G4 V8 O% c4 Zmin. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the
) F& i& _ c6 l' y2 ^- v/ psample is turned through 90° about the centre line of the cord guard.
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( v' d9 u7 ~8 J翻译成中文的主要意思就是：' e/ a; p) Y9 V# d/ D
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The oscillating member is moved backwards and forwards through an angle of 90° (45° on ( A2 ^- i6 E# g" K$ u& f
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per ! a; _ i' }9 O! F6 t, |
min. - 摇摆装置能够在90°的范围内前后摆动（其中这个90°指的是沿垂直位置两边各45°），以每分钟60次的频率摇摆20000次。
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! X# X7 q1 S( a/ m% C; J0 Y9 S这句话讨论的是仪器的摆动机构要满足的特性，就是要能在90°的范围内前后摆动，如果只能在45°的范围内摆动的话，这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。
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After 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后，将样品沿着电线防护套的中心线转动90°。* f8 U% a- r5 T
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这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已，同样没有涉及到摆动周期的解释和说明。
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最重要的一句话应该是：A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动，无论是向后还是向前的。
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: p' X0 E4 {/ l1 p8 Z这句话虽然容易引起歧义，但是仔细考虑一下也不是很难理解。可以看出，1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动，那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。* D$ Z2 E/ |4 N, Q& S+ A
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摘抄UL 745-1标准中的相关章节如下，关于这个问题解释的非常清楚，供大家参考参考：
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A flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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发表于 2009-5-7 20:39
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