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发表于 2009-5-8 15:06
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引用第10楼franco于2009-05-07 20:39发表的 :/ w) w2 K/ A3 t/ l v4 g. \
The oscillating member is moved backwards and forwards through an angle of 90° (45° on ) y+ t, i# s! K$ B3 s( D8 W: D
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per , a# O; ]) u0 i* a+ i
min. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the 5 _& j8 M4 {* e1 f
sample is turned through 90° about the centre line of the cord guard.
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....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。
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翻译成中文的主要意思就是:
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5 p, E B; W! L+ TThe oscillating member is moved backwards and forwards through an angle of 90° (45° on
! j. @& B; O8 p8 ] T8 Y, ueither side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per # z) f4 o2 j: J7 m4 P
min. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。) Z. j3 y. `3 u8 n2 y7 r6 s N
) b' C3 `* z* t2 @) F这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。3 G+ f* w$ D, }+ ^1 Q
+ [. N% @) k' C6 A7 X$ G+ aAfter 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。
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n& Z, }( `- `( F- r0 e这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。+ H/ v" W: f, e4 K. j B& Y+ z
9 P) P, k4 \1 r0 @! @最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。# }! L1 j( `9 ~6 N+ O5 N
9 e# `3 j5 C$ l1 O' V这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。
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摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:) m! X) k: P/ v$ r1 e o$ @6 m# S% Q
+ N/ U$ p3 s0 K! zA flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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