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| DSH 3874 G9 B% j+ G0 F4 W
7 |- o) F) ^8 k0 j | Hazardous Voltage
; V1 t. t1 A9 |" s" h+ h | 1.2.8.3 / 12.8.4
$ O* L. {8 O7 t+ R, y9 D | 60950(ed.2) & 60950(ed.3)
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Standard:; e7 E3 T$ {3 N3 H8 b4 |- L' U# o
IEC60950, 2nd (3rd) Edition" W5 ]+ H- l1 {" ~4 O+ t( `
Sub clause:3 G0 M' f$ w8 x' U' b
1.2.8.3(1.2.8.4)
' V: V7 m% X' e! k: ?" }$ mSheet n. 387 L5 _# s& H* x( R
Page 1 (1)' h: r+ g: c, |9 Q1 ]
Subject:, B) e7 U- l6 P" v( G
Hazardous Voltage/ u" O& ~2 H% i) ]9 F8 p% i' ?
Key words:
& I( F+ a1 w% v3 v, z4 U1 d& C-Hazardous Voltage) U! c; t3 B: O
Decision confirmed+ l- F, u @3 E+ Z) I- G; b
at CTL 38th meeting( |! L9 ^0 E, q/ F8 o9 o% v: ]
Question:
8 f, V- [4 [; W" cWhich of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance
0 h2 s% \& n' H+ L4 ?( ^8 L8 U4 `criteria, in order to determine whether the voltage shown in the graph is hazardous or not?# G1 N5 o/ T. e; W- }
Condition: The circuit that generates this voltage is not a limited current circuit.
! ~5 X& `+ c% JDecision:" Y/ l+ v2 L4 B% `2 C
This voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.3
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