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求解：标准中有说电量的计算是通过2000 Ω电阻，测出电压/时间曲线，求出电路二端的放电电量。好久没用高数了，对于此电压/时间曲线，如何计算？积分公式是怎样的？4 L2 ~% ^4 ] X. M$ z" z
F% V8 w+ [, D+ @; p$ pIf protective impedance is used, the current between the part and the supply source shall
3 i: M. A$ i* u8 e9 w# C- Hnot exceed 2 mA for d.c., its peak value shall not exceed 0,7 mA for a.c. and
& H' }- Z1 ~$ p% X) O! g' i' q– for voltages having a peak value over 42,4 V up to and including 450 V, the capacitance: s j! x& Z1 w$ g( j
shall not exceed 0,1 μF;
1 j+ X g: P5 T6 X! f9 v# Z' ~– for voltages having a peak value over 450 V up to and including 15 kV, the discharge shall6 U% I; W. p3 }4 E' d& Q5 n
not exceed 45 μC;
% `. e& W. O' i' I6 a; i' {. D0 F0 k– for voltages having a peak value over 15 kV, the energy in the discharge shall not exceed5 X9 x9 I0 [8 K
350 mJ.
3 e6 V6 K6 Z, E3 r$ S5 GCompliance is checked by measurement, the appliance being supplied at rated voltage.
( S; L, E9 r D3 Q, ^4 zVoltages and currents are measured between the relevant parts and each pole of the supply Q. H+ w' H, {4 P4 Z
source. Discharges are measured immediately after the interruption of the supply. The# j" F6 a* S: K8 g
quantity of electricity and energy in the discharge is measured using a resistor having a5 s- O! E: x# L3 q5 C Q
nominal non-inductive resistance of 2 000 Ω .
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发表于 2016-8-15 16:43
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